Problem:
Find and graph the tangent line to the curve represented by the following pair
of parametric equations:
x = t2 + 1, y = t3 - t
at t = 1.5 using the TI-85 graphing calculator.
Visualization:

[Press here to see animation again!]
- If you are not familiar with the graphing of functions on the TI-85,
then first read the
Initial Setup
page from
Little's Basic Guide to the TI-85.
- In order to graph a system of parametric equations, the calculator must be
in the PARAM graphing mode. To change into this mode, press 2nd MODE. You should see a screen similar to the following:

- Using the arrow keys, move the blinking cursor to the PARAM item of
the fifth row and press the ENTER key.
- Press the EXIT key.
- Press the GRAPH key and then pick E(t)=
by pressing the F1 key.
- If necessary, keep pressing F4 key until only
the two items xt1= and yt1= appear on the screen.
- At the prompt xt1=, type in
t ^ 2 + 1
and press the ENTER key.
- At the prompt yt1=, type in
t ^ 3 - t
and press the ENTER key.
- The range settings for the graph above are

- Pick the item GRAPH from the menu by pressing the F5 key.

- Press the MORE key so that MATH appears on
the menu. Pick MATH by pressing the F1 key.
- Press the MORE key again so that TANLN
appears on the menu. Pick TANLN by pressing the F1 key.
- Press the right arrow key until the value t = 1.5 appears in the
left lower corner of the screen:

A blinking cursor indicates the point on the curve corresponding to t = 1.5. The coordinates of the point, x = 3.25 and y = 1.875 appear
at the bottom of the screen.
- Press the ENTER key to draw the tangent line and
to calculate its slope which appears at the bottom of the screen, dy/dx = 1.9166666667.

Hence, the equation of the tangent line is
y - 1.875 = 1.9166...(x - 3.25).